Durgun holden Harekete başlayarak bir elektronu Işık hızının% 40 ‘ina – [Free] B55
Durgun holden Harekete başlayarak bir elektronu Işık hızının% 40 ‘ina kadar hizlandirmak icin ne kadarWhe belo potansigel forke intiyag vardir? (lish haz; c=3×108ms, elektroncen yous; q=-1,6×10-19C, elektronun withesi (:me=9,11×10-31lg
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Answer
⚡ Potential Difference to Accelerate Electron to 40% of the Speed of Light
To find the potential difference required to accelerate an electron from rest to 40% of the speed of light, we use the principle of conservation of energy.
🌟 Step 1 — Concept
The work done by the electric field equals the kinetic energy gained by the electron:
where:
- q = electron charge =
1.6 × 10-19 C - m = electron mass =
9.11 × 10-31 kg - c = speed of light =
3 × 108 m/s - v =
0.4 × c
🌟 Step 2 — Kinetic Energy
The kinetic energy of the electron at v = 0.4c is given by:
Substituting the values:
Calculating step by step:
🌟 Step 3 — Calculating Potential Difference
Rewriting the energy equation:
Substituting the known values:
Result:
✨ Final Answer
Thus, a potential difference of about 41 kV is needed to accelerate an electron from rest to 40% of the speed of light.